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Engineering Mathematics Core Change of rings

Radical of Matrix and Power Series Rings

Two constructions transport the Jacobson radical predictably: radMn(R)=Mn(radR) entrywise, and radR[[t]] is exactly the set of power series whose constant term lies in radR.

Page ID
KEVOS-ENG-MATH-NCR-0043
Taxonomy
ENG / ENG-MATH
Collection
noncommutative-rings-core
Source
§5, Exercises 5.x (pp. 74–81)
Reviewed
2026-08-08
Version
1.0.0

01Executive Summary

Most change-of-ring questions about rad are hard. Two are not. For a full matrix ring the radical is computed entry by entry, radMn(R)=Mn(radR); for a formal power series ring it is the preimage of radR under evaluation at t=0, so radR[[t]]=radR+tR[[t]]. Both answers hold for an arbitrary ring with identity, with no chain condition and no commutativity.

The two results come from different mechanisms — matrix units on one side, convergent geometric series on the other — and it is worth seeing both, because between them they explain why the polynomial ring R[t] resists description and why that resistance is equivalent to a famous open problem.

Mn(radR)radMn(R)
radR+tR[[t]]radR[[t]]
Ex. 5.6Lam's power series exercise
NoneHypotheses on R

02Overview

Section 5 of Lam asks how rad moves between a ring and an extension of it. The general results — the Behaviour of the Radical under Ring Extensions page — give one-way inclusions under hypotheses such as *R is an R-module direct summand of S* or *S is generated over R by elements centralising R*. The two constructions on this page are the cases where those inclusions can be sharpened all the way to equalities and stated in closed form.

radMn(R)=Mn(radR),radR[[t]]={f∈R[[t]]:f(0)∈radR}
(5.M)

The two closed formulas of this page. The first is Lam's Example 7 in §4; the second is Exercise 5.6.

The one thing to remember

Matrices expand the radical entrywise; power series enlarge it by the whole ideal tR[[t]], because every element of 1+tR[[t]] is a unit. Neither statement needs R to be commutative, artinian or noetherian.

The first formula is the reason rad is a Morita invariant, which in turn is why Wedderburn–Artin theory can be applied after passing to R/radR without worrying about matrix size. The second is the reason power series rings are the standard supply of noncommutative local rings, as used on the Local Rings page.

The contrast with R[t] is instructive and is not a defect of exposition: Amitsur's theorem says radR[t]=N[t] for a nil ideal N⊆R, but identifying N with the upper nilradical Nil∗R is equivalent to Köthe's conjecture.

03Learning Objectives

  • Prove radMn(R)=Mn(radR) for an arbitrary ring R and every n≥1.
  • Deduce Mn(R)/radMn(R)≅Mn(R/radR) and the Morita invariance of the radical.
  • Prove that f∈R[[t]] is a unit exactly when f(0)∈U(R), and derive radR[[t]]=radR+tR[[t]].
  • Extend the power series computation to the skew ring R[[x;σ]] for σ∈Aut(R).
  • Compute rad for upper triangular and generalised triangular matrix rings.
  • Explain why R[[t]] is never left artinian and Mn(R) is never local for n≥2.

04Definitions

Definition(5.M.1)The two constructions

For a ring R with identity and n≥1, Mn(R) denotes the ring of n×n matrices over R, with matrix units Eij satisfying EijEkℓ=δjkEiℓ. For a two-sided ideal I⊆R, Mn(I) denotes the set of matrices all of whose entries lie in I; it is a two-sided ideal of Mn(R).

R[[t]] denotes the ring of formal power series f=∑i≥0aiti with ai∈R and t central. Evaluation at zero, ev0(f)=a0, is a surjective ring homomorphism R[[t]]→R with kernel tR[[t]].

Mn(I) versus I⋅Mn(R)
These coincide for a two-sided ideal I: every matrix with entries in I is a finite sum ∑aijEij with aij∈I.
ev0
The constant-term homomorphism R[[t]]→R. Its kernel tR[[t]] is the ideal of series with zero constant term.
R[[x;σ]]
Formal power series ∑i≥0aixi with the rule xr=σ(r)x for an automorphism σ of R. Multiplication is well defined because each coefficient of a product is a finite sum.
Tn(R)
The subring of Mn(R) of upper triangular matrices. Its strictly upper triangular part is a nilpotent ideal of index n.
Semiprimitive
radR=0; also called Jacobson semisimple or J-semisimple.

All rings have an identity, all modules are unital, and n is a finite positive integer throughout. The finiteness of n is used in both proofs of the matrix theorem.

05Core Concepts

Two mechanisms for transporting the radical

It helps to separate the two arguments before reading either proof, because they generalise in different directions.

Mechanism A

Matrix units move entries

Because E1iAEj1=aijE11, membership of a matrix in a two-sided ideal is equivalent to membership of each of its entries in the corresponding ideal of R. The radical, being a two-sided ideal, is therefore detected one entry at a time.

Mechanism B

Geometric series converge

In R[[t]] the sum ∑i≥0(tg)i makes sense because only finitely many terms contribute to each coefficient. So 1−tg is a unit for every g, and tR[[t]] is forced inside the radical by the maximality property (4.5).

Why the second mechanism gives a preimage

Once an ideal 𝔄 is known to lie inside radA, the quotient rule (4.6) applies: rad(A/𝔄)=(radA)/𝔄. Taking A=R[[t]] and 𝔄=tA, whose quotient is R, converts the problem into a computation in R and returns the answer as a preimage.

1+tA⊆U(A)⟹tA⊆radA⟹rad(A/tA)=(radA)/tA⟹radA=ev0−1(radR)

This is a template, not a one-off. Any surjection A↠R whose kernel consists of quasi-regular elements and is an ideal computes radA from radR in exactly the same way — nilpotent kernels, T-nilpotent kernels and complete filtrations all qualify.

Where the polynomial ring falls outside both

R[t] has no ideal playing the role of tR[[t]]: 1−tg is a unit of R[t] only in degenerate cases, since degrees add. And R[t] is not a matrix ring over R. Neither mechanism applies, and the correct answer — Amitsur's radR[t]=N[t] with N nil — needed a genuinely new argument.

06Key Results

Theorem§4, Example 7Radical of a full matrix ring

Let R be any ring with identity and let n≥1. Then

radMn(R)=Mn(radR).

That is, a matrix lies in the radical of Mn(R) if and only if each of its n2 entries lies in radR.

Proof

Write J=radR.

**Mn(J)⊆radMn(R).** Since J is a two-sided ideal of R, Mn(J) is a two-sided ideal of Mn(R). By the maximality property (4.5) it is enough to show that In+A∈U(Mn(R)) for every A∈Mn(J). Induct on n. For n=1 this is (4.5) in R. For n>1 put U=In+A=(uij), so u11=1+a11∈U(R) and ui1=ai1∈J for i≥2. Left-multiplying U by the invertible matrices In−ui1u11−1Ei1 for i=2,…,n clears the first column below the diagonal and produces

U′=(u11v0W),W=(uij−ui1u11−1u1j)2≤i,j≤n.

For i≥2 the correction term ui1u11−1u1j lies in J, because ui1∈J and J is an ideal. Hence W=In−1+A′ with A′∈Mn−1(J), so W∈U(Mn−1(R)) by the inductive hypothesis. A block upper triangular matrix with invertible diagonal blocks is invertible — explicitly, the inverse of U′ is (u11−1−u11−1vW−10W−1) — and U is a product of invertible matrices with U′, hence invertible.

**radMn(R)⊆Mn(J).** Let A=(aij)∈radMn(R) and fix indices i,j. The radical is a two-sided ideal, so E1iAEj1=aijE11 also lies in it. Fix b∈R and set d=baij. Applying (4.1) inside Mn(R) with the element bE11, the matrix In−(bE11)(aijE11)=In−dE11 is left-invertible: there is C=(ckℓ) with C(In−dE11)=In. Comparing (1,1) entries gives c11−c11d=c11(1−d)=1, so 1−baij is left-invertible in R. As b was arbitrary, (4.1) gives aij∈J.

The two inclusions give the stated equality.

Corollary(5.M.2)Consequences for matrix rings

Let R be a ring and n≥1. Then:

  1. Mn(R)/radMn(R)≅Mn(R/radR);
  2. Mn(R) is semiprimitive if and only if R is semiprimitive;
  3. (radMn(R))m=Mn((radR)m) for every m≥1, so radMn(R) is nilpotent of index m exactly when radR is;
  4. for R≠0 and n≥2, Mn(R) is never a local ring.
Proof

(1) Entrywise reduction Mn(R)→Mn(R/radR) is a surjective ring homomorphism with kernel Mn(radR)=radMn(R). (2) is immediate since Mn(I)=0 forces I=0. (3) follows from Mn(I)Mn(I′)=Mn(II′) for two-sided ideals I,I′, which holds because Eik can be used to place any product aa′ in any position. (4) A ring is local exactly when its quotient by the radical is a division ring; by (1) that quotient is Mn(R/radR), and for n≥2 this contains the nonzero zero-divisors E11,E22 with E11E22=0.

Lemma(5.M.3)Units of a power series ring

For any ring R and f∈R[[t]]: f∈U(R[[t]]) if and only if f(0)∈U(R).

Proof

If f is a unit then so is its image under the ring homomorphism ev0. Conversely let a0=f(0)∈U(R) and write f=a0+th with h∈R[[t]]. Since t is central, f=a0(1+tg) with g=a0−1h. The series ∑i≥0(−tg)i is a well-defined element of R[[t]], since the coefficient of tm receives contributions only from the terms with i≤m, and it is a two-sided inverse of 1+tg. Hence f∈U(R[[t]]).

TheoremEx. 5.6Radical of a formal power series ring

Let R be any ring with identity and A=R[[t]] with t a central indeterminate. Then

radA=ev0−1(radR)={a+tf(t):a∈radR,f∈A}=radR+tA.

In particular A∩radA=radR under the identification of R with the constant series, and A/radA≅R/radR.

Proof

The ideal tA is two-sided, and 1+tA⊆U(A) by (5.M.3) since every element of 1+tA has constant term 1. By the maximality property (4.5), tA⊆radA.

Because tA is an ideal contained in radA, the quotient rule (4.6) gives rad(A/tA)=(radA)/tA. The isomorphism A/tA≅R induced by ev0 identifies the left-hand side with radR. Therefore (radA)/tA corresponds to radR, i.e. radA=ev0−1(radR)=radR+tA. The two final statements follow by restricting ev0 to constants and by the first isomorphism theorem.

Corollary(5.M.4)Consequences for power series rings

Let R≠0 be a ring and A=R[[t]]. Then:

  1. A is never semiprimitive, since 0≠t∈radA;
  2. radA is never nil, since t is not nilpotent; consequently A is never left artinian, by (4.12);
  3. A is local if and only if R is local, and then the residue division rings agree: A/radA≅R/radR;
  4. A is semilocal if and only if R is semilocal.
Proposition(5.M.5)Skew power series

Let R be a ring, σ an automorphism of R, and A=R[[x;σ]] the skew power series ring with xr=σ(r)x. Then xA=Ax is a two-sided ideal, A/xA≅R, and

radR[[x;σ]]=radR+xA.

The proof is that of the untwisted case verbatim: rx=xσ−1(r) shows Ax⊆xA, geometric series still converge x-adically, and radR is invariant under every automorphism of R, so the constant-term description is unambiguous.

Proposition(5.M.6)Triangular matrix rings

Let R be a ring and Tn(R)⊆Mn(R) the ring of upper triangular matrices. Then

radTn(R)={(aij)∈Tn(R):aii∈radR for 1≤i≤n}.

More generally, if A and B are rings and M is an (A,B)-bimodule, the generalised triangular ring (AM0B) has radical (radAM0radB).

Proof

In the two-block case, 𝔑=(0M00) is a two-sided ideal with 𝔑2=0, hence 𝔑⊆rad by (4.11). The quotient by 𝔑 is A×B, whose radical is radA×radB because units in a product are componentwise units. Now (4.6) identifies the radical with the preimage, which is the stated ideal. The Tn(R) statement is the same argument with 𝔑 the strictly upper triangular matrices, an ideal with 𝔑n=0 and quotient R×⋯×R (n factors).

Remark(21.10), (21.14)The structural explanation

For any idempotent e∈R the corner ring theorem states rad(eRe)=eRe∩radR=e(radR)e. Taking R=Mn(S) and e=E11 gives eRe≅S, and e is a full idempotent, so the ideal correspondence for eRe matches radMn(S) with radS. This is Lam's second derivation of the matrix formula, and it is the one that generalises: it is really a statement about Morita equivalence, developed on the Corner Rings page.

07Proof Techniques and Method

How these proofs work, and which move to reuse elsewhere.

Move 1

Squeeze with (4.5) then (4.6)

To compute radA, find an ideal 𝔄 with 1+𝔄⊆U(A) and a recognisable quotient A/𝔄. Then 𝔄⊆radA by (4.5) and radA is the preimage of rad(A/𝔄) by (4.6).

Move 2

Conjugate by matrix units

E1iAEj1=aijE11 turns any statement about matrices in a two-sided ideal into a statement about single entries. Combined with (4.1) this needs only left-invertibility, so no Dedekind-finiteness is assumed.

Move 3

Row reduce inside the radical

Gaussian elimination works over any ring provided the pivots are units. Entries of In+A with A in the radical give pivots in 1+radR, which are units by (4.5), and the corrections stay in the radical because it is an ideal.

Move 1 is the reusable one. It computes the radical of R[[t]], of Tn(R), of R[t]/(tm), of any ring complete with respect to a filtration, and of any surjection with nilpotent or T-nilpotent kernel. When no such kernel exists — as for R[t] — expect the problem to be hard.

Move 3 makes the finiteness of n explicit: the induction terminates after n pivots. Nothing in the argument survives to matrices of infinite size, where the elimination never finishes.

08Worked Example

A finite matrix ring

Take R=ℤ/12ℤ, whose radical is (2)∩(3)=(6)={0,6}. Then

radM2(ℤ/12ℤ)=M2((6)),
(E.1)

Sixteen matrices, all four entries drawn from {0,6}.

Two checks. First, M2((6))2=M2((6)(6))=M2((36))=M2(0)=0, so the radical is nilpotent of index 2 — as it must be, since M2(ℤ/12) is finite hence artinian. Second, the unit test: I2+(6666)=(7667) has determinant 49−36=13≡1(mod12), a unit, so the matrix is invertible.

The quotient is M2(ℤ/12)/M2((6))≅M2(ℤ/6ℤ)≅M2(𝔽2)×M2(𝔽3), which is semisimple — exactly what (5.M.2)(1) predicts.

A local power series ring, then matrices over it

Let R=ℤ(p), the localisation of ℤ at the prime p, a local ring with radR=pR and residue field 𝔽p. Put A=ℤ(p)[[t]]. By the power series theorem,

radA=pR+tA=pA+tA,
(E.2)

The ideal generated by p and t — every series whose constant term is divisible by p.

Then A/radA≅R/pR≅𝔽p, so A is local. Note that radA contains t, which is not nilpotent, so radA is not nil and A is not artinian — consistent with (5.M.4), and a reminder that local is far weaker than artinian local.

Now stack the constructions: M3(A) has radM3(A)=M3(pA+tA) and

M3(A)/radM3(A)≅M3(𝔽p),
(E.3)

Simple artinian of 𝔽p-dimension 9. So M3(A) is semilocal but not local and not artinian.

Order of operations does not matter

Mn(R[[t]])≅Mn(R)[[t]], and the two formulas agree on the nose: a matrix of series has all constant terms in Mn(radR) exactly when, read as a series of matrices, its constant term lies in Mn(radR).

09Process and Workflow

Peel off matrix layersReplace Mn(S) by S; the radical returns entrywise at the end. This shrinks the working dimension by a factor n2.
Peel off complete or nilpotent layersReplace S[[t]] by S, or S→S/𝔑 for a nilpotent ideal 𝔑. Record each kernel; the final answer is their sum with the pullback of the base radical.
Reduce to a corner if possibleIf a full idempotent e is visible, work in eRe, which is often much smaller, and transport back by (21.10).
Compute the base radicalNow the ring is small: a finite-dimensional algebra, a finite ring or a field. Use the standard algorithms.
Reassemble and verifyPush the answer back through the layers, then test 1+rad⊆U on a few elements.

Which route applies to your construction?

Matrices or a cornerUse the entrywise formula or (21.10). The answer is exact, needs no hypotheses on the base ring, and preserves semiprimitivity in both directions.
Completion or nilpotent kernelUse (4.5) and (4.6): the radical is the preimage of the base radical. Expect the result to be non-nil, so do not assume artinian behaviour.
Polynomial variables adjoinedOnly Amitsur's theorem is available: the radical is N[T] for a nil ideal N of R, and pinning down N is open in general.
Scalars extended along a field extensionSeparable algebraic extensions behave, by (5.17); transcendental ones give only a nil intersection, by (5.15). See the Radical under Field Extension page.

10Comparison and Classification

The radical under standard constructions
ConstructionRadicalHypothesesReference
Mn(R)Mn(radR)any R, n finite§4, Example 7
Tn(R) upper triangulardiagonal entries in radR, rest arbitraryany R(5.M.6)
eRe, e=e2e(radR)eany R, any idempotent(21.10)
R[[t]]radR+tR[[t]]any REx. 5.6
R[[x;σ]]radR+xR[[x;σ]]σ∈Aut(R)(5.M.5)
R×SradR×radSany R, Scomponentwise units
R[t]N[t] with N=R∩radR[t] nilany R; N not identified(5.10)
R[T], R commutative(NilR)[T]R commutative(5.1)
R⊗kK(radR)⊗kKK/k separable algebraic(5.17)
Which properties each construction preserves
Radical in closed formR semiprimitive ⇒ so is itradR nilpotent ⇒ its radical nilpotentR local ⇒ so is it
Mn(R), n≥2●yes●yes●yes○no
Tn(R), n≥2●yes○no●yes○no
eRe, e≠0●yes●yes●yesyes, trivially
R[[t]]●yes○no○no●yes
R[[x;σ]]●yes○no○no●yes
R[t]open●yes●yes○no

Which properties each construction preserves

The single row that matters most is the last: R[t] preserves semiprimitivity (if radR=0 then R has no nonzero nil ideal, so radR[t]=0 by Amitsur's theorem) yet its radical has no closed form. Preservation of a property and computability of the invariant are different questions. The nilpotence column reads yes for R[t] for a cheap reason: N=R∩radR[t] is nil, hence contained in radR by (4.11), so radR nilpotent forces N[t] nilpotent. The eRe entry in the last column is equally cheap: a local ring has no idempotents other than 0 and 1, so eRe=R.

11Relationship Map

Both theorems on this page are instances of a single containment pattern, and the pattern is what to remember when meeting a new construction.

  • Computing rad of a constructed ring — three routes, in order of preference
    • Morita route — the construction is a matrix ring or a full corner
      • radMn(R)=Mn(radR)
      • rad(eRe)=e(radR)e
      • radical is a Morita invariant
    • Filtration route — an ideal 𝔄 with 1+𝔄⊆U(A) and known quotient
      • 𝔄 nilpotent: triangular rings, R[t]/(tm)
      • 𝔄 topologically nilpotent: R[[t]], R[[x;σ]]
      • answer is rad of the quotient, pulled back
    • Neither route available — polynomial and group ring extensions
      • radR[t]=N[t], N nil — Amitsur
      • is N=Nil∗R? equivalent to Köthe's conjecture
      • radkG for infinite G: hard, section 6
𝔄 ideal, 1+𝔄⊆U(A)⟹𝔄⊆radA by (4.5)⟹radA/𝔄=rad(A/𝔄) by (4.6)⟹radA known

12Applications and Industry Use

Applications here means where this structure is used — inside mathematics and in the engineering and computing disciplines that consume it.

Symbolic computation

Dimension reduction before decomposition

A finite-dimensional algebra presented as Mn(S) has n2dimS structure constants. Since the radical is entrywise, a system computes radS and expands, replacing an O((n2d)3) linear algebra problem by an O(d3) one.

Modular representation theory

Coefficients in a complete local ring

Brauer theory works over a complete discrete valuation ring such as ℤp or ℤ(p)[[t]] precisely because completion makes the coefficient ring local with a known radical, so reduction modulo the residue field is controlled.

Coding theory

Codes over chain and Galois rings

Linear codes over ℤ/pm and over finite chain rings are analysed via the filtration by powers of the radical; the matrix formula is what lets generator matrices over the ring be reduced to the residue field entry by entry.

Control and systems theory

Formal solutions and delay systems

Transfer function algebras over k[[t]] and skew power series rings k[[x;σ]] model time-varying and delay systems. Invertibility of a transfer matrix reduces, by the two theorems here, to invertibility of its constant term over the residue ring.

The honest summary is that these are structural results consumed inside algebra: they are what make radical a Morita invariant and what supply the standard examples of noncommutative local rings. Their engineering visibility is indirect, through computer algebra libraries and through coding and systems models built over local coefficient rings.

13Standards and Notation

Standards here covers notation, symbol and markup standards, and reference implementations, rather than material or design codes.

Matrix ringMn(R) in this collection; Rn×n and Matn(R) occur elsewhere
Radical of itMn(radR), equal to (radR)⋅Mn(R)
Power seriesR[[t]] or R[[x]]; the double bracket is standard, R[|t|] is a rare variant
Twisted versionR[[x;σ]] with xr=σ(r)x; some authors write R[[x,σ]] or place σ on the left
Constant termf(0), ev0(f) or ε(f) for the augmentation
ImplementationsPowerSeriesRing in Sage and Magma; MatrixAlgebra plus RadicalOfAlgebra in GAP

Reading older sources

Pre-1970 texts often write semisimple for what is here called semiprimitive. Statements such as *Mn(R) is semisimple iff R is* are therefore ambiguous: under the modern reading they need R left artinian as well, under the older reading they are exactly (5.M.2)(2).

14Computational Notes

Computational notes cover algorithms, cost and library behaviour rather than manufacturing process.

  • **Never compute in Mn directly.** Radical algorithms for a d-dimensional algebra cost roughly O(d3) field operations; applied to Mn(S) with dimS=d that is O(n6d3). Computing radS and expanding is a factor n6 cheaper.
  • Power series are decidable at the constant term. Membership in radR[[t]] and invertibility in R[[t]] both depend only on the coefficient of t0, so no truncation error is involved in either test.
  • Truncations agree. In R[t]/(tm) the ideal (t) is nilpotent, so the same argument gives rad(R[t]/(tm))={f:f(0)∈radR}. This is the representation a computer algebra system actually stores.
  • Library entry points. GAP exposes RadicalOfAlgebra, Magma JacobsonRadical, Sage A.radical(); all require a finite-dimensional algebra over a field, and all will happily accept a matrix algebra without exploiting the entrywise structure unless the base algebra is supplied separately.
  • No algorithm for the polynomial case. Since identifying R∩radR[t] in general is equivalent to Köthe's conjecture, there is no procedure that returns generators of radR[t] for an arbitrary ring R.

Finiteness is not decorative

Both the row-reduction proof and the matrix-unit proof use n<∞. For rings of infinite matrices — row-finite, column-finite or otherwise — the entrywise formula is not available and the radical must be determined by other means.

15Failure Modes and Common Mistakes

radR[[t]]≠(radR)[[t]]

Only the constant term is constrained. For R=k a field, (radk)[[t]]=0 while radk[[t]]=(t)≠0. The correct description is ev0−1(radR); the containment (radR)[[t]]⊆radR[[t]] is proper whenever R≠0.

(radR)[t] need not lie in radR[t]

Adjoining a polynomial variable can destroy radical elements, whereas adjoining a power series variable cannot. By Amitsur's theorem R∩radR[t] is nil, so for R=k[[x]] — where radR=(x) contains no nonzero nilpotent — we get radR[t]=0 even though radR≠0. The two constructions point in opposite directions.

Mn(R) is not local for n≥2

Locality is not preserved by matrix expansion: Mn(R)/radMn(R)≅Mn(R/radR) is a division ring only when n=1. What matrix rings over local rings are is semiperfect, which is a different statement.

  • Do not read the triangular formula as *all entries in radR*: the off-diagonal entries are unconstrained, and for R a division ring the radical of Tn(R) is the whole strictly upper triangular part, not zero.
  • Do not assume R[[t]] inherits chain conditions from R: for R≠0 it is never left artinian, because t lies in the radical and is not nilpotent.
  • Do not apply (4.6) to an ideal that is not inside the radical; the quotient rule fails badly otherwise, as ℤ→ℤ/4 shows.
  • Do not transplant the entrywise formula to rings of infinite matrices, or to non-unital rings of finitary matrices, without a fresh proof.

16Quick Reference

Matrix ringradMn(R)=Mn(radR), any R, n finite
Matrix quotientMn(R)/rad≅Mn(R/radR)
Power seriesradR[[t]]=radR+tR[[t]]
Power series quotientR[[t]]/rad≅R/radR
Unitsf∈U(R[[t]])ifff(0)∈U(R)
Cornerrad(eRe)=e(radR)e
Triangulardiagonal in radR, off-diagonal free
PolynomialradR[t]=N[t], N nil — not identified
Property transfer at a glance
QuestionMn(R)R[[t]]
Semiprimitive when R is?yes, and converselynever, for R≠0
Local when R is?only for n=1yes, same residue ring
Left artinian when R is?yesnever, for R≠0
Radical nilpotent when radR is?yes, same indexno, t is not nilpotent
Radical meets R in radR?yes, on scalar matricesyes, on constants

17Frequently Asked Questions

Why is the matrix formula entrywise while the power series formula constrains only the constant term?

Because the mechanisms differ. In Mn(R) the matrix units conjugate any entry into the (1,1) position, so a two-sided ideal cannot contain a matrix without containing all matrices with those entries — membership is forced entry by entry. In R[[t]] nothing moves coefficients around; instead the whole ideal tR[[t]] is swallowed by the radical because 1−tg is invertible by a convergent geometric series. The radical is then simply the preimage of radR.

Is the Jacobson radical a Morita invariant?

Yes. radMn(R)=Mn(radR) together with the corner ring theorem rad(eRe)=e(radR)e for a full idempotent e gives invariance under the generators of Morita equivalence. Concretely, R and Mn(R) are semiprimitive together, semilocal together and semiperfect together, and their radical quotients correspond.

Does R[[t]] inherit chain conditions from R?

Not the descending one. For R≠0 the element t lies in radR[[t]] and is not nilpotent, so the radical is not nilpotent and R[[t]] cannot be left artinian, by (4.12) — even when R is a field. This is the standard reminder that a local ring need not be an artinian local ring.

What is the analogue for infinite matrix rings?

There is none of this form. Both proofs given here use n<∞: the row reduction terminates after n pivots, and the ideal correspondence for Mn(R) is a finite-matrix statement. Rings of row-finite or column-finite infinite matrices need separate analysis, and the naive entrywise guess should not be assumed.

Why does the polynomial ring behave so much worse than the power series ring?

Degrees add in R[t], so 1−tg is essentially never a unit and no analogue of tR[[t]] is available inside the radical. Amitsur's theorem (5.10) still gives radR[t]=N[t] with N=R∩radR[t] nil, but deciding whether N is the upper nilradical Nil∗R is Problem (5.12), equivalent to Köthe's conjecture.

Does the skew case need σ to be an automorphism?

The proof as given does. Bijectivity of σ is what makes xA=Ax a two-sided ideal with quotient R; for a merely injective endomorphism the left and right ideals generated by x can differ, and the clean preimage description is not justified without further hypotheses.

18Related KEVOS Topics

Corner RingsFor any idempotent e, the corner eRe is a ring with identity e whose radical is exactly e(rad R)e, and whose ideals embeRadical under Ring ExtensionsTwo one-way results control the radical across a ring extension: a splitting or fixed-point hypothesis forces R rad S ⊆ Local RingsA nonzero ring is local when it has exactly one maximal left ideal — equivalently, exactly one maximal right ideal, eqRadical of Polynomial RingsFor a commutative ring R and any nonempty set T of commuting indeterminates, rad R[T] = Nil(R[T]) = (Nil R)[T]: adjoininJacobson Rings and the NullstellensatzA Hilbert (Jacobson) ring is one in which every prime is an intersection of maximal ideals, so rad = Nil throughout. The

19References

  1. T. Y. Lam, A First Course in Noncommutative Rings, Graduate Texts in Mathematics 131, Springer-Verlag, 1991: §4, Example 7 following (4.15) (pp. 60–62) for the matrix ring; §5, Exercise 6 (p. 82) for the power series ring; §5 (pp. 70–81) for the surrounding change-of-rings results.
  2. T. Y. Lam, A First Course in Noncommutative Rings, §21, (21.10)–(21.14), for the corner ring theorem and the idempotent-theoretic derivation of the matrix formula.
  3. T. Y. Lam, Exercises in Classical Ring Theory, 2nd edition, Problem Books in Mathematics, Springer-Verlag, 2003, solutions to the exercises of §5.
  4. N. Jacobson, Structure of Rings, American Mathematical Society Colloquium Publications 37, revised edition, 1964, Chapter I.
  5. F. W. Anderson and K. R. Fuller, Rings and Categories of Modules, 2nd edition, Graduate Texts in Mathematics 13, Springer-Verlag, 1992, §15 and §21–22 for the radical and Morita equivalence.
  6. S. A. Amitsur, “Radicals of polynomial rings”, Canadian Journal of Mathematics 8 (1956), 355–361.

20AI Suggested Questions

  • Prove the corner ring theorem rad(eRe)=e(radR)e and deduce the matrix formula from it.
  • What is the Jacobson radical of the ring of row-finite ω×ω matrices over a division ring?
  • Give a ring R with radR≠0 but radR[t]=0, and explain what Amitsur's theorem says about it.
  • Compute radR[[x;σ]] when σ has finite order, and compare with the fixed subring Rσ.
  • Show that R and Mn(R) are semiperfect together, and identify what happens to idempotent lifting.
  • Why is Problem (5.12) equivalent to Köthe's conjecture, and what would a counterexample look like?
  • Determine the radical of the Laurent series ring R((t)) when R is a division ring, and when R is local.
  • How do these formulas interact with completion: is rad of an inverse limit the inverse limit of the radicals?
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KEVOS® Knowledge Library — reviewed 2026-08-08

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